Tuesday, 10 October 2023

Dyeing off 100% cotton knit fabric with reactive dye.

 

Experiment name : Dyeing off 100% cotton knit fabric with reactive dye.

Theory: Nowadays reactive dyes are very popular for textile coloration because of its some specific properties like colour fastness, wide range of shade, brilliance of shade and simple application procedure. It reacts with fibre in presence of alkali and adheres as a part of fibre.

Objective:
1.       To learn about dyeing process of cotton fabric by reactive dye.
2.       To dye cotton fabric by reactive dye.

Nature of sample:
Pre-treated 100% cotton knit fabric.

Apparatus required:
1.Beakers
2.Glass Rod.
3.Pipette.
4. Measuring Cylinder.
5. Digital Balance.
6. Tri-pod stand.
7. Gas Burner.
8. Thermometer.
9. Pot.

Process sequence
  • Collection of pre-treated sample
  • Set water level
  • Add leveling agent
  • Add dye solution
  • Add salt solution'
  • Add soda ash solution
  • Add fabric sample
  • Raise the temperature to 60deg C
  • Run time for 30 minute
  • Bath drop
  • Rinsing
  • Hot wash at 90deg for 10 minute
  • Dry





Table1: Dyeing Recipe
SL
Process Parameter
Unit
Dossing
Stock soln:
01
Levelling Agent
g/L
1
1%
02
Dyes
%
2
1%
03
Glauber Salt
g/L
40
15%
04
Soda Ash
g/L
10
10%
05
Sample Weight
gm
5
---
06
M:L
-----
1:30
---
07
Temperature
degC
60
---
08
Time
min
20
----


Calculation:
Total Liquor = Fabric weight X L  [M:L = 01:30]
                                = 5 X 30
                                = 150mL

Dye 2%  = (Fabric weight X x%) / stock solution%
                = (5X2%) / 1%
                =10mL

Levelling Agent = (Total liquor X 'x'g/L) / (stock solution%  X 1000)
                                = (150 X 1) / 1% X 1000
                                = 15ml

Glauber Salt = (Total liquor X 'x'g/L) / (stock solution%  X 1000)
                                = (150 X 40) / 15% X 1000
                                = 40mL

Soda Ash = (Total liquor X 'x'g/L) / (stock solution%  X 1000)
                                = (150 X 1) / 1% X 1000
                                = 15ml

Initial Water = total liquor - (chemical 1 + chemical 2 + chemical 3 ...)
                = 150- (15+40+15+10) mL
                = 150 -80 mL
                = 70mL

Process Curve:







Sample Attachment:



Observation/comment: >>>>>>>>>>>

Conclusion: >>>>>>>>>>>

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